Commander V 130A and Resistor Question

[ccpecot]

I cannot find the answer to question in the Scorpion manual and wondered if someone here may know the answer.

As far as the resistor is concerned, is it necessary to unplug it before plugging in my packs? Or do just keep the resistor plug in and plug in the packs and ready to go?

Thanks for any help!
Dom

[Costas]

Hi Dom,

The resistor is connected in line with the positive lead.

So when this part of the lead is open circuit the resistor is effectively in circuit. When you connect the two red bullets together you effectively short out the resistor rendering it not in use.

Connect your battery to the ESC with the two red bullets open circuit [resistor is now limiting/passing current]. Once battery is connected, you then simply connect the two red bullets together which 'shorts' the resistor and removes it from the circuit.

The idea of the resistor is to have it in circuit when first connecting the battery. The resistor limits the inrush current which prevents your battery connectors from producing any damaging sparks. Once the battery is connected the resistor has done its job and can be bypassed by connecting the two red bullets together.

Note that you should not leave the resistor in circuit for too long a period as it can heat up reasonably quickly.

[jockew]

If you're using the internal BEC I suggest that you do NOT use the spark suppressor, keep the connector on the red wire plugged in. The resistor will heat up very quickly, within 1 second it can be hot enough to burn your fingers.

See these threads:
https://www.helifreak.com/showthread.php?t=384027
https://www.helifreak.com/showthread.php?t=374946

[ccpecot]

Originally Posted by jockew

If you're using the internal BEC I suggest that you do NOT use the spark suppressor, keep the connector on the red wire plugged in. The resistor will heat up very quickly, within 1 second it can be hot enough to burn your fingers.

See these threads:
https://www.helifreak.com/showthread.php?t=384027
https://www.helifreak.com/showthread.php?t=374946

Thanks as well for the input and links to the threads! For my setup, I chose not to use the internal BEC. I appreciate the input!
Dom

Originally Posted by Costas

Hi Dom,

The resistor is connected in line with the positive lead.

So when this part of the lead is open circuit the resistor is effectively in circuit. When you connect the two red bullets together you effectively short out the resistor rendering it not in use.

Connect your battery to the ESC with the two red bullets open circuit [resistor is now limiting/passing current]. Once battery is connected, you then simply connect the two red bullets together which 'shorts' the resistor and removes it from the circuit.

The idea of the resistor is to have it in circuit when first connecting the battery. The resistor limits the inrush current which prevents your battery connectors from producing any damaging sparks. Once the battery is connected the resistor has done its job and can be bypassed by connecting the two red bullets together.

Note that you should not leave the resistor in circuit for too long a period as it can heat up reasonably quickly.

Thanks Costas for nice explanatory posts! I will do that!
Take care,
Dom