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Old 09-01-2010, 05:59 AM   #17 (permalink)
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Originally Posted by monocleman View Post
I wonder what happens when large amp draws are used. I suppose the internal resistance R = Vdrop / I should stay the same up to the max discharge rate? And then what?
If you would exceed the manufacturer’s maximum discharge rating with a very low rated resistor, it would be almost like shortening the cells. The current wouldn’t be able to go much higher anymore. But the resistance is a fixed low value in this example, and to respect R=U/I, the voltage would need to drop heavily. Which it will do, because you are destroying the cells in fact. Making for a (permanent) high IR value. And a damaged pack.
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